Linear motion

Hello guys i'm Jonathan and i will describe things that i've learned at school especially on physics.

Quantities:

Distance

Displacement

Speed

Velocity

Acceleration

Average value of velocity and acceleration

Instantaneous of velocity and acceleration

Equation of linear motion

Equation 1 : Equation related between initial velocity, final velocity, acceleration and distance. There is no time factor in it.

Equation 2 : Relation between distance travelled, initial velocity, acceleration and time.

Equation 3 : Relation between initial velocity, final velocity, acceleration and distance. There is no time factor in it.

Initial velocity : Vo

Final velocity : Vt

Time : T

Acceleration : A

Change of velocity : Vt-Vo

Equation 1 comes from,

The rate of change of velocity or the acceleration

A=(Vt-Vo)/t    atau

Vt=Vo+at

Equation 2 comes from,

Displacement = average velocity * time = [(vo+v1)/2]*t

Vt=vo+at

Substituting for vt, we get D

D=[(vo+vo+at)/2]*t

= vot+at^2/2

D=Vot+at^2/2

Equation 3 comes from,

vt=vo+at

Squaring, we get

Vt^2=(Vo+at)^2 = Vo^2+ 2Voat+a^2 t^2

=Vo^2+2a(Vot+at^2/2)

Vt^2=Vo^2+2ad

Falling object ( if going up gravitation will be -10 M/S^2)

Vt=vo+gt 

D=Vot+gt^2/2

Vt^2=Vo^2+2gs

e.g

A car

Vo/speeding at : 30m/s

acceleration : (-5)m/s^2

Vt/it will stop : 0m/s

Find how long it will cross more if the line of traffic light is 88 M ahead

0^2=30^2+ 2*((-5)*D

0= 900 + (-10)*D

10 D = 900

D=90M

90M-88M= 2 Meter

A car

Vo/speeding : 10m/s

Vt/it will stop : 30m/s

Time taken : 10 seconds

Distance ; ?

Acceleration : ?

Find acceleration and then find the distance.

Acceleration : 30-10/10 = 2 m/s^2

Distance = o*10+2*10^2/2

=0+ 100

=100 Meter

Thank you ^^